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Expanding Logarithms

 

When you are asked to expand log expressions, your goal is to express a single logarithmic expression into many individual parts or components. The best way to illustrate this concept is to show a lot of examples. In this lesson, there are eight worked problems.

The key in successfully expanding logarithms is to carefully apply the rules of logarithms. Take time to go over the rules and understand what they are trying to "say".

For instance Rule 1 is called the Product Rule. What it does is break the product of expressions as sum of log expressions. See the rest of the descriptions below

 

Rules of Logarithms
list of the rules of logarithms

 


 

  Study the description of each rule to get an intuitive understanding of it.
Rule1: Product Rule product rule of logarithms: log(MN) base b = log M base b + log N base b The logarithm of the product of numbers is the sum of logarithms of individual numbers.
Rule 2: Quotient Rule quotient rule of logarithms: log (M/N) base b = log (M) base b - log (N) base b The logarithm of the quotient of numbers is the difference of the logarithm of individual numbers.
Rule 3: Power Rule power rule of logarithms: log (M^k) base b = k*log (M) base b The logarithm of an exponential number is the exponent times the logarithm of the base.
Rule 4: Zero Rule zero rule of logarithms: log (1) base b = 0 The logarithm of 1 with b > 1 equals zero.
Rule 5: Identity Rule identity rule of logarithms: log (b) base b = 1 The logarithm of a number equal to its base equals 1, with b > 1, equals one.
Rule 6: Log of Exponent Rule log (b^k) base b = k The logarithm of an exponential number where its base is the same as the base of the log equals the exponent.
Rule 7: Exponent of Log Rule b^log (k) base b = k Rasing the logarithm of a number by its base equals the number.

 

Example 1: Expand the log expression example 1: log (3xyk) base 5.

Looking inside the parenthesis, we see a product of number and variables. The Product Rule doesn't say that there should only be two factors inside, in fact, there could be more. Okay, so we'll separate the main log expression as sum of four logs.

answer: log(3xyk) base 5 = log(3) base 5 + log(x) base 5 + log(k) base 5

 

Example 2: Expand the log expression example 2: log [7x/y] base 2.

The inside of the parenthesis is a fraction that means I will first apply the Quotient Rule. Since the numerator is a product of 7 and x,  I use Product Rule to break it up.

answer: log [7x/y] base 2 = log(7) base 2 + log(x) base 2 - log(y) base 2

 

Example 3: Expand the log expression example 3: log [36m^3/sqrt(n)] base 6.

Okay, so this one is also in fraction so Quotient Rule is the first step. But now there's something "new" in this problem.

That is, the numerator contains a variable with exponent. This should be easy since Rule 3 or Power Rule can easily handle it. Just bring the exponent down to the left, that's it!

In addition, there's a radical expression in the denominator. Remember that a radical can be expressed as fractional exponent. Since this radical is square root that means the power is just ½.

 

answer :  log [36m^3/sqrt(n)]  base 6 =  2+ 3*log(m) base 6 - (1/2) * log(n) base 6

 

Also, this is the first time we see Rule 5 or Identity Rule of logarithm in action. Expect to apply this rule more often because it is extremely useful in the simplification process.

Example 4: Expand the log expression example 4: log√(7x^3y) base 2 .

Don't let that square root symbol scare you. Just think of it as the power or exponent of ½. So this problem is reduced to expanding a log expression with a power of ½. This is where the Power Rule brings down that exponent ½ to the left of log, and then you expand the rest as usual.

solution: log√(7x^3y) base 2 = (1/2)*[ log 7 base 2 + 3* log x base 2 + log y base 2]

 

Example 5: Expand the log expression example 5: log [ (x*sqrt(y)/h]^4  base 7.

This problem is quite interesting because the entire expression is being raised to some power. In addition, the presence of a square root on the numerator adds some level of difficulty.

However, if we stick to the basics by carefully applying the rules of exponents in every step, we should have no problem conquering this problem! Let's plan out our course of action, okay?

Bring down that exponent 4 using Power Rule. Next, use the Quotient Rule to express the fraction as difference of log expressions. And finally, don't forget that square root is just a fractional exponent of ½.

 

answer: log [ (x*sqrt(y)/h]^4  base 7 = 4*log(x) base 7 + 2* log(y) base 7 - 4* log(h) base 7

 

I distributed the 4 into the grouping symbol to get rid of the fraction 1/2. Although it's okay to leave the 4 outside. Either of the two answers should be correct.

 

Example 6: Expand the log expression example 6: log [m/5yk]^(1/3) with base 10.

It's just a cube root of some rational expression. Replace the cube root symbol by a fractional power of 1/3. That exponent of 1/3 can be brought down using the Power Rule of logarithm.  Now we have just to deal the rational expression using the Quotient Rule, then finish it off using the Product Rule.

 

answer: log [m/5yk]^(1/3) with base 10 = (1/3) * (log m base 10 - log 5 base 10 - log y base 10 - log k base 10)

 

Don't get distracted by the different types of grouping symbols. The idea is to make sure that we are applying the logarithm rules correctly in each step that we undertake, without committing algebraic mistakes such as distributing -1 into the grouping symbol.

 

Example 7: Expand the log expression log [64*sqrt(x)*sqrt(y)] base 4.

I would immediately apply the Product rule to separate the factors into sum of logarithmic terms. Numerically simplify the log464 since 64 can be expressed as exponential number with base 4, that is 64 = 43. Deal with the square roots by replacing them with fractional power, and then use Power Rule of log to bring it down in front of the log symbol as multiplier.

log [64*sqrt(x)*sqrt(y)] base 4 = 3 + (1/2) log (x) base + (1/2) log (y) base y

 

Example 8: Expand the log expression log (4*sqrt(y)/cube root x)^3.

The main power 3 can be placed out front as multiplier using the Power Rule. The Quotient rule should deal with the fractional expressions by writing them as the difference of logs. Now, replace the square root radical by power of 1/2 and the cube root by power of 1/3.

answer is 6 + (3/2) * log (y) with base 2 - log (x) base 2

 

 


 

Practice Problems with Answers
Worksheet 1

 

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